Solve 3^2x+1 = 5(3^x) + 2
I would know how to solve it if it was only 3^2x+1, but now it seems more complicated.
let u = 3^x
Then your equation becomes
3^(2x+1) = 5*3^x + 2
3*3^(2x) = 5*3^x + 2
3u^2-5u-2 = 0
...
I would know how to solve it if it was only 3^2x+1, but now it seems more complicated.
Then your equation becomes
3^(2x+1) = 5*3^x + 2
3*3^(2x) = 5*3^x + 2
3u^2-5u-2 = 0
...