Three charges are produced on the Verticus of the squareof side 1m then find the resultant force on any one of the corner.
To find the resultant force on any one of the corners of a square due to three charges, we need to consider the electrical forces exerted by each charge and calculate the net force.
Let's assume that the square lies in the xy-plane, with one corner at the origin (0,0). We'll label the other three corners as A, B, and C, respectively.
The formula to calculate the electrical force between two charges is given by Coulomb's Law:
F = k * (q1 * q2) / r^2
Where:
- F is the electrical force between the charges,
- k is the electrostatic constant (approximately equal to 9 x 10^9 N * m^2 / C^2),
- q1 and q2 are the magnitudes of the charges,
- r is the distance between the charges.
For our scenario, let's assume the charges at the vertices of the square have the same magnitude, q. We'll refer to the charges at A, B, and C as q1, q2, and q3, respectively.
Since all three charges are the same magnitude, and the distances from each corner to any adjacent corners are equal, the magnitudes of the electrical forces on each corner due to the other charges will be equal.
Now, let's consider the forces acting on one of the corners, like A. To calculate the net force, we need to find the vector sum of the forces acting on A due to the other charges.
Since the forces are equal in magnitude and opposite in direction (due to the symmetry of the square), they will cancel each other out along the diagonal passing through A.
Therefore, the net force acting on any one of the corners of the square due to three charges will be zero.