Pre-Calculus

a ferris wheel is elevated 1 meter above ground. When car reaches the highest point of the Ferris wheel, it's altitude from ground level is 31 metres. How far away from the center, horizontally, is the car when it is at an altitude of 25 meters?

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  1. so, the radius of the wheel is 15 m
    ...(31 - 1) / 2

    when the altitude is 25 m, the car is 9 m above the center
    ... 25 - 15 - 1

    using Pythagoras,
    ... hypotenuse (radius) is 15 m
    ... vertical side is 9 m
    ... horizontal side is ?

    HINT (a big one)
    ... it's a Pythagorean triple, 3-4-5

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  2. x2 + (y - 16)2 = 225
    x2 + (25 + 16) = 225
    x2 + 81 = 225
    x2 = 225 - 81
    x2 = 144 -> squared 144 to illiminate the square in
    x2
    so.. x = 12

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