a ferris wheel is elevated 1 meter above ground. When car reaches the highest point of the Ferris wheel, it's altitude from ground level is 31 metres. How far away from the center, horizontally, is the car when it is at an altitude of 25 meters?

x2 + (y - 16)2 = 225

x2 + (25 + 16) = 225
x2 + 81 = 225
x2 = 225 - 81
x2 = 144 -> squared 144 to illiminate the square in
x2
so.. x = 12

so, the radius of the wheel is 15 m

...(31 - 1) / 2

when the altitude is 25 m, the car is 9 m above the center
... 25 - 15 - 1

using Pythagoras,
... hypotenuse (radius) is 15 m
... vertical side is 9 m
... horizontal side is ?

HINT (a big one)
... it's a Pythagorean triple, 3-4-5

Paano nakuha ang 16

How did you get the number 16?

A ferris wheel is elevated 1 m above ground. When a car reaches the highest point on the

ferris wheel, its altitude from ground level is 31 m. How far away from the center,
horizontally, is the car when it is at an altitude of 25 m?

Why did the car go to the Ferris wheel's therapist? It had some serious altitude issues!

But to answer your question, let's do some math!

We know that the difference in altitude between the highest point and the ground is 31 - 1 = 30 meters.

Now, we want to find out how far away from the center, horizontally, the car is when it is at an altitude of 25 meters.

We can set up a proportion:

30 meters (difference in altitude) is to the radius of the Ferris wheel as 25 meters (altitude) is to the horizontal distance from the center.

So, let's calculate:

30 / R = 25 / X

Cross-multiplying, we get:

30X = 25R

Dividing both sides by 25, we have:

X = (30/25) * R

Simplifying further:

X = (6/5) * R

Now, the radius of the Ferris wheel is the sum of the height above the ground (1 meter) and the altitude at the highest point (31 meters).

R = 1 + 31 = 32 meters

Plugging in the value of R, we find:

X = (6/5) * 32

X = 38.4 meters

So, when the car is at an altitude of 25 meters, it is approximately 38.4 meters away from the center horizontally. Though, I hope it doesn't develop any separation anxiety!

To find the horizontal distance from the center when the car is at an altitude of 25 meters, we can use the concept of right triangles and trigonometry.

Let's assume that the center of the Ferris wheel is point O, and the horizontal distance from the center to the car is x meters. Also, let point A represent the car at an altitude of 25 meters, and point B represent its highest point at an altitude of 31 meters. Finally, let C represent the ground level.

We can form a right triangle ABC, where AB represents the vertical distance (altitude) and BC represents the horizontal distance (x).

Using this triangle, we can apply the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

In our case, AC represents the hypotenuse, and we have the following information:
AC = 31 meters (distance to the highest point of the Ferris wheel)
AB = 31 - 1 = 30 meters (vertical distance from the ground to the highest point)
BC = x meters (horizontal distance from the center to the car at an altitude of 25 meters)

Now, we can write the equation using the Pythagorean theorem:
AC^2 = AB^2 + BC^2

Plugging in the values we know:
31^2 = 30^2 + x^2

Simplifying the equation:
961 = 900 + x^2

Rearranging the equation to isolate x:
x^2 = 961 - 900
x^2 = 61

Taking the square root of both sides:
x = √61

Therefore, when the car is at an altitude of 25 meters, it is approximately √61 meters away from the center horizontally.