Algebra 1 B Unit 6: Rational Expressions and Func
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posted by Steve
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(3+7x)(16x2+15x2) (3+1x)(12x+16+0+18x2) Q4: (15+13x2+14x2)+(13x+18x) Q5: (2x2+1+15x2+7+3)+(0x+17x) Q6: (18x+3)+(17x2+1x2+9+8+0x) Q7: (6x + 14)  (9x + 5) Q8: (14x2 + 13x + 12)  (7x2 + 20x + 4) Q9: Subtract 10x2 + 16x  15 from
asked by Anonymous on January 10, 2007 
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(3+7x)(16x2+15x2) (3+1x)(12x+16+0+18x2) Q4: (15+13x2+14x2)+(13x+18x) Q5: (2x2+1+15x2+7+3)+(0x+17x) Q6: (18x+3)+(17x2+1x2+9+8+0x) Q7: (6x + 14)  (9x + 5) Q8: (14x2 + 13x + 12)  (7x2 + 20x + 4) Q9: Subtract 10x2 + 16x  15 from
asked by Anonymous on January 10, 2007 
BobPursley..here it is:
Problem 1: (x2)/(3x+4)  6x/(x+1) What I did: Common denominator is: (3x+4)(x+1) (x2)(x+1)/(3x+4)(x+1)  6x(3x+4)/(x+1)(3x+4) [(x2)(x+1)  6x(3x+4)] / (x+1)(3x+4) (x^2  x  2  18x^2  24x) / (x+1)(3x+4) x^2  18x^2 = 17x^2
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Solve: 5x3=11+12x; 17x3=11; 17x3+3=11+3= 17x=14; x= 14/17 is this right?
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Math help Steve?
1) Given that p(3), p(1), and p(5)=0, which expression could be p(x)? A)x^3x^217x15 B)x^3+x^217x+15 C)x^33x^213x+15 D)x^39x^2+23x15 Hi Steve, I got what you said, but how would I solve this equation then?
asked by Alan on April 29, 2015 
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1) Given that p(3), p(1), and p(5)=0, which expression could be p(x)? A)x^3x^217x15 B)x^3+x^217x+15 C)x^33x^213x+15 D)x^39x^2+23x15 I would appreciate if someone could show me how to solve it
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asked by Alpha on May 30, 2017 
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1) Given that p(3), p(1), and p(5)=0, which expression could be p(x)? A)x^3x^217x15 B)x^3+x^217x+15 C)x^33x^213x+15 D)x^39x^2+23x15 How do I solve it? Please help
asked by Anonymous on February 1, 2016