a cube of side 6cm is placed in graduated measuring cylinder 20 ml of watercis then added and the cubes remains at the bottom of the cylinder what will be calculated amount
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I have this same question i dont get it lol
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a liter is 10 cm * 10 cm * 10 cm
or 1000 cm^3
so
a mL is 1 cm^3
so
20 mL is 20 cm^2
we added a volume of:
6 cm * 6 cm * 6 cm is 216 cm^3
so
if the cube is submerged, the scale on the side of the cylinder should now read 236 cm^3
by the way you sure that cube is not 6 mm on a side?
236
To calculate the amount of water displaced by the cube, we need to determine the volume of the cube. The volume of a cube can be found by multiplying the length of one side by itself twice.
In this case, the cube's side length is 6 cm. So, the volume of the cube would be:
Volume = side length³
Volume = 6 cm x 6 cm x 6 cm
Volume = 216 cm³
Now, let's calculate the amount of water displaced. We know that 20 ml of water was added, which is equivalent to 20 cm³. Since the cube remains at the bottom of the cylinder, it implies that the cube completely displaces the water, and there is no additional water above it.
Therefore, the calculated amount in this case would be 216 cm³.