LCD
1.1/2 4/x^2 <<1/2 or 2
2.1/z;3/7z << HELP
3. 3/5;x/x+2 << Help
4. 3m/m+n; 3n/m-n<< Help
I need help or equations on how to solve this please
you need a denominator which is the least common multiple of the given denominators.
For example, if you have 2/3 and 3/5, the LCD is 3*5
So, these work the same way.
#1: 2x^2
#2: 7z
#3: 5(x+2)
#4: (m+n)(m-n)
Thank you! I didn't rea;;y understand it, but this helped
To find the least common denominator (LCD) for each set of fractions, follow these steps:
1. Identify the denominators of the fractions in the set.
2. Determine the factors of each denominator.
3. Multiply each factor by the greatest power of any repeated prime numbers among the denominators.
4. Multiply the resulting factors together to obtain the LCD.
Now, let's apply these steps to the given sets of fractions:
1. To find the LCD for the fractions 1/2 and 4/x^2:
The denominators are 2 and x^2.
The factors of 2 are 2 and 1.
The factors of x^2 are x and x.
The LCD is 2 * x * x = 2x^2.
2. To find the LCD for the fractions 1/z and 3/7z:
The denominators are z and 7z.
The factors of z are z and 1.
The factors of 7z are 7, z, and 1.
The LCD is 7 * z = 7z.
3. To find the LCD for the fractions 3/5 and x/(x+2):
The denominators are 5 and (x+2).
The factors of 5 are 5 and 1.
The factorization of (x+2) cannot be simplified further.
The LCD is 5 * (x+2) = 5x + 10.
4. To find the LCD for the fractions 3m/(m+n) and 3n/(m-n):
The denominators are (m+n) and (m-n).
The factorization of (m+n) cannot be simplified further.
The factorization of (m-n) cannot be simplified further.
The LCD is (m+n) * (m-n) = (m^2 - n^2).
By finding the LCD for each set of fractions, you can then use it to add, subtract, or compare the fractions.