Plss help
(3b-4a)(3b-4a)
Use the FOIL method
Farthest: Multiply the 3b variables together.
Outside: Multiply the outside 2 variables together.
Inside: Multiply the inside 2 variables together.
Left: Multiply the 2 variables on the left side toghether.
this is a perfect square.
(x-y)^2 = x^2-2xy+y^2
Now just substitute in
x = 3b
y = 4a
Certainly! The expression you have is (3b-4a)(3b-4a). To simplify this expression, we can use the distributive property of multiplication.
Let's take it step by step:
First, we multiply the first terms of the binomials:
(3b)*(3b) = 9b^2
Next, we multiply the outer terms:
(3b)*(-4a) = -12ab
Then, we multiply the inner terms:
(-4a)*(3b) = -12ab
Finally, we multiply the last terms of the binomials:
(-4a)*(-4a) = 16a^2
Now, we can combine these simplified terms:
9b^2 - 12ab - 12ab + 16a^2
To combine like terms, we combine the "b^2" terms together:
9b^2 - 24ab + 16a^2
So, the simplified form of (3b-4a)(3b-4a) is 9b^2 - 24ab + 16a^2.