a car moves 300m due north and then 60mdue south .what is the distance covered by the car and what is its dislacement
"Distance" is the sum of distances travelled, irrespective of direction, just like the odometer on a car.
"displacement" is the distance and angle of the final position relative to the initial position, irrespective of how and where intermediate stops are made.
For the given problem, the car moved:
300m due north and 60m due south, so the total distance travelled is ?
Since it travelled 300m due north and 60m due south, the end position is at 240m due north from the original position. What is the displacement?
240
To find the distance covered by the car, you need to add the distances traveled in each direction.
Distance Covered = Distance North + Distance South
Distance North = 300m
Distance South = 60m
Distance Covered = 300m + 60m = 360m
So, the car covered a total distance of 360 meters.
To find the displacement of the car, you need to determine the straight-line distance from the starting point to the final position.
Displacement = Final Position - Initial Position
In this case, the car moves 300m due north and then 60m due south. Since the car ends up south of its starting point, the displacement is in the opposite direction, south.
Displacement = -60m
So, the car's displacement is -60 meters, indicating that it moved 60 meters south of its starting point.