Algebra

1. The length of a rectangle is twice its width. The perimeter of the rectangle is 24 inches. Write a system of equations in 2 variables. Use substitution to solve the problem.
A. Equation 1: L = 2W
L= 2(4) = 8

Equation 2: 2L + 2W = 24
2(2W) + 2W = 24
6W = 24
W = 24/6 = 4

(i would like help checking the Equations)

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  1. ERquation 1.

    L = 2 W

    2 W = L

    Equation 2.

    2 W + 2 L = 24

    Substitution: 2 W = L

    L + 2 L = 24

    3 L = 24

    L = 24 / 3 = 8 in

    L = 2 W

    8 = 2 W

    8 / 2 = W

    W = 4 in

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