# Algebra

1. The length of a rectangle is twice its width. The perimeter of the rectangle is 24 inches. Write a system of equations in 2 variables. Use substitution to solve the problem.
A. Equation 1: L = 2W
L= 2(4) = 8

Equation 2: 2L + 2W = 24
2(2W) + 2W = 24
6W = 24
W = 24/6 = 4

(i would like help checking the Equations)

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1. ERquation 1.

L = 2 W

2 W = L

Equation 2.

2 W + 2 L = 24

Substitution: 2 W = L

L + 2 L = 24

3 L = 24

L = 24 / 3 = 8 in

L = 2 W

8 = 2 W

8 / 2 = W

W = 4 in

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