Find the final temperature, given that the initial temperature of a 40 g piece of Aluminum is 25 degrees Celsius and it is heated with 1800 J of heat. The specific heat capacity of Aluminum is 0.903
q = mc(Tfinal-Tinitial)
1800 =40*0.903(Tf=25)
Am I supposed to multiply everything on the right side then divide it by 1800?
You're stuck with the math.
You clear the parentheses first.
1800 = 40*0.903*Tf - 40*0.903*25
Now combine terms, then
Solve for Tf, the only unknown in the equation. That's the final T.
To find the final temperature of the aluminum piece, we can use the equation q = mcΔT, where q is the heat energy transferred, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
In this case, the initial temperature (Ti) is 25 degrees Celsius, the mass (m) is 40 g, the heat energy (q) is 1800 J, and the specific heat capacity (c) is given as 0.903 J/g°C.
First, let's rearrange the equation to solve for the change in temperature (ΔT):
ΔT = q / (mc)
Now substitute the given values:
ΔT = 1800 J / (40 g * 0.903 J/g°C)
Calculating the numerator:
ΔT = 1800 / (36.12)
Simplifying:
ΔT ≈ 49.92 °C
To find the final temperature (Tf), we add the change in temperature (ΔT) to the initial temperature (Ti):
Tf = Ti + ΔT
Tf = 25°C + 49.92°C
Tf ≈ 74.92 °C
Therefore, the final temperature of the aluminum piece is approximately 74.92 degrees Celsius.