For an experiment, we used 10 mL of HCl. We are then to find the moles of it without any other information given. Is this right?

(10 mL HCl)* (1.19 g / mL) = 11.9 g HCl
(11.9 g HCl) * (1mol/36.46064 g)
= 0.326 mols HCl

Were you given this density value?

(1.19 g / mL) ?

A published value for concentrated HCl at 1.19 g/mL has a molarity of 12.39 M. (see ref)

Value of molarity obtained from density is very approximate.

Ref:
https://en.wikipedia.org/wiki/Hydrochloric_acid

No I was not given the density value? What is recommended to go from mL to moles instead?

No I was not given the density value.*

How do you expect to get from mL to moles if you do not know how much HCl is in the water? Where did you get the 1.19 ? That is why we do not understand your answer.

Abby, you need either the molarity of the HCl or some way to calculate the molarity. The density will do it or the molarity will do it; otherwise, it can't be done. Expecting to convert mL to mols without knowing how strong the solution is is like asking how many apples there are in a bushel without knowing the size of the apples.

Yes, your calculation looks correct. To find the moles of HCl, you can use the given volume (10 mL) and the density of HCl (1.19 g/mL) to convert to grams of HCl. Then, you can use the molar mass of HCl (36.46064 g/mol) to further convert grams to moles.

Here's a breakdown of the calculations:

1. Convert mL to grams:
(10 mL HCl) * (1.19 g / mL) = 11.9 g HCl

2. Convert grams to moles:
(11.9 g HCl) * (1mol/36.46064 g) = 0.326 mol HCl

Therefore, you have 0.326 moles of HCl for the given 10 mL volume.