TV screens are measured on the diagonal. If we have a TV-cabinet that is 72 inches long and 64 inches high, how large a TV could we put in the space (leave 2-inches on all sides for the edging of the TV)? Round your answer to the nearest tenth.

(72 - 2 - 2)^2 + (64 - 2 - 2)^2 = D^2

TV screens are measured on the diagonal. If we have a TV-cabinet that is 70 inches long and 58 inches high, how large a TV could we put in the space (leave 2-inches on all sides for the edging of the TV)? Round your answer to the nearest tenth.

To determine the size of the TV that can fit in the given space, we need to calculate the diagonal length of the available area.

Using the Pythagorean theorem (a^2 + b^2 = c^2), where "a" and "b" are the width and height of the TV cabinet, and "c" is the diagonal length, we will subtract 4 inches (2 inches on each side) from the width and 4 inches from the height.

So, the calculations would be as follows:

Width of available space: 72 inches - (2 inches + 2 inches) = 68 inches
Height of available space: 64 inches - (2 inches + 2 inches) = 60 inches

Next, we can calculate the diagonal length using the Pythagorean theorem:

Diagonal length = √(Width^2 + Height^2)

Diagonal length = √(68^2 + 60^2)
Diagonal length = √(4624 + 3600)
Diagonal length = √(8224)
Diagonal length ≈ 90.7 inches

Therefore, the largest TV that can fit in the given space, leaving a 2-inch edging on all sides, would have a diagonal length of approximately 90.7 inches (rounded to the nearest tenth).

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