For the reaction C + 2H2 -> CH4
How many grams of hydrogen are required to produce 145 grams of methane, CH4
1. Write and balance the equation. You have that.
2. mols CH4 = grams/molar mass = ?
3. Using the coefficients in the balanced equation, convert mols methane to mols H2. For every mols CH4 you will need 2 mols H2.
4. Now convert mols H2 to grams H2.
grams H2 = mols H2 x molar mass H2 = ?
This 4 step procedure works for all stoichiometry problems. With a slight modification it works on limiting regent problems also.
18.3
Well, let's calculate it together, with a touch of humor!
To determine the grams of hydrogen required, we need to look at the balanced equation. We see that 1 mole of methane (CH4) is produced from 2 moles of hydrogen (H2).
So, first let's convert the grams of methane (CH4) to moles. The molar mass of methane is approximately 16 grams/mole.
145 grams CH4 x (1 mole CH4 / 16 grams CH4) = ? moles CH4
Now that we have the moles of methane, we can use the mole ratio from the balanced equation to find the moles of hydrogen (H2).
? moles CH4 x (2 moles H2 / 1 mole CH4) = ? moles H2
And finally, we can convert the moles of hydrogen to grams using the molar mass of hydrogen, which is approximately 2 grams/mole!
? moles H2 x (2 grams H2 / 1 mole H2) = ? grams H2
So, to find the grams of hydrogen required to produce 145 grams of methane, we will need to plug in the appropriate values and do the math. It's time for some number juggling!
But remember, even though I'm a Clown Bot, I take math seriously. So let's crunch those numbers and find the answer!
To determine the number of grams of hydrogen required to produce 145 grams of methane (CH4), we need to use stoichiometry. Stoichiometry is the calculation of the quantities of reactants and products involved in a chemical reaction.
First, we need to balance the chemical equation:
C + 2H2 -> CH4
The coefficient in front of H2 indicates that it takes 2 moles of hydrogen gas to produce 1 mole of methane.
Next, we need to convert the mass of methane (CH4) to moles. We can do this by using the molar mass of methane, which is the sum of the atomic masses of carbon (C) and hydrogen (H) in the molecule.
The molar mass of C = 12.01 g/mol
The molar mass of H = 1.01 g/mol
Molar mass of CH4 = (12.01 g/mol) + 4 * (1.01 g/mol) = 16.05 g/mol
Now, we can calculate the number of moles of methane:
Moles of CH4 = Mass of CH4 / Molar mass of CH4
Moles of CH4 = 145 g / 16.05 g/mol ≈ 9.03 mol
Since the stoichiometric ratio between H2 and CH4 is 2:1, we know that it takes 2 moles of H2 to produce 1 mole of CH4. Therefore, to produce 9.03 moles of CH4, we need:
Moles of H2 = 2 * Moles of CH4
Moles of H2 = 2 * 9.03 mol = 18.06 mol
Finally, we can convert the moles of hydrogen to grams by multiplying by the molar mass of hydrogen:
Mass of H2 = Moles of H2 * Molar mass of H2
Mass of H2 = 18.06 mol * 2.02 g/mol = 36.49 g
Therefore, approximately 36.49 grams of hydrogen are required to produce 145 grams of methane, CH4.