A 1200Kg car travels at a constant speed of 26m/s for 5s up a 130m long hill. The total height of the hill is 27m & the friction force acting on the car is 2520N.

What power was used by the car in traveling up the hill?

I know that Fnet=o bc velocity is constant, therefore Fapp=2520N

I used (Fapp * d)/t so (2520 * 130)/5 to get 6.55 * 10^4

I got it incorrect... Am I supposed to do something with the height distance as well?

Thanks a bunch! :D

work against friction is

... 2520 N * 130 m

change in gravitational potential is
... m g h = 1200 kg * g * 27 m

the sum is the total energy

energy divided by time (5 s) is the power

To calculate the power used by the car in traveling up the hill, you need to consider both the work done and the time taken. Here's how you can get the answer:

1. Calculate the work done by the car. Work is defined as the force applied multiplied by the distance traveled in the direction of the force. In this case, the force applied is the friction force acting on the car, which is 2520N. The distance traveled in the direction of the force is the length of the hill, which is 130m. Therefore, the work done by the car is:

Work = Force * Distance = 2520N * 130m = 327,600 J

2. Calculate the time taken to travel up the hill. The car travels at a constant speed of 26 m/s for 5 seconds, so the time taken is 5 seconds.

3. Calculate the power used by the car. Power is defined as the rate at which work is done, which is equal to the work done divided by the time taken. Therefore, the power used by the car is:

Power = Work / Time = 327,600 J / 5s = 65,520 W

So, the correct answer is 65,520 W or 65.52 kW.