Cup A has 50% pink balls and 50% green balls. Cup B has 50% orange balls and 50% green balls. You and you friend both draw one chip from each bowl. What is the probability that you both draw at least one white chip?

By white i mean green.

50%

the key word is "at least one green chip"

there are 3 possibilities

1. green, non-green = .5(.5) = .25
2. non-green,green = .25
3 green, green = .25

so the prob of at least one green = .75 or 75%

To find the probability that you both draw at least one white chip, we need to calculate the complement of the event where both chips are non-white.

Let's start by calculating the probability that both chips are non-white.

In Cup A, there are only pink and green chips. Since 50% of the chips in Cup A are pink, the probability of drawing a non-white chip from Cup A is 1 - 0.50 = 0.50.

Similarly, in Cup B, there are only orange and green chips. Since 50% of the chips in Cup B are orange, the probability of drawing a non-white chip from Cup B is also 1 - 0.50 = 0.50.

To find the probability of both chips being non-white, we multiply the probabilities together:

P(both non-white) = P(non-white from A) * P(non-white from B)
= 0.50 * 0.50
= 0.25

Now, we need to find the complement of this event, which is the probability of drawing at least one white chip. The complement of an event A is given by 1 - P(A).

So, the probability that you both draw at least one white chip is:

P(at least one white) = 1 - P(both non-white)
= 1 - 0.25
= 0.75

Therefore, the probability that you both draw at least one white chip is 0.75, or 75%.