The current in a simple electrical circuit is inversely proportional to the resistance. If the
current is 80 amps when the resistance is 30 ohms, find the current when the resistance is
12 ohms
To find the current when the resistance is 12 ohms, we can use the concept of inverse proportionality.
Let's denote the current as "I" and the resistance as "R". We know that I is inversely proportional to R, which can be written as:
I ∝ 1/R
We can express this relationship using a proportion:
I1 / R1 = I2 / R2
where I1 is the initial current, R1 is the initial resistance, I2 is the current we want to find, and R2 is the resistance we want to find.
Plugging in the given values, we have:
80 / 30 = I2 / 12
To solve for I2, we can cross multiply and solve for I2:
80 * 12 = 30 * I2
960 = 30 * I2
Dividing both sides by 30:
I2 = 960 / 30
I2 = 32 amps
Therefore, the current when the resistance is 12 ohms is 32 amps.
To find the current when the resistance is 12 ohms, we can use the concept of inverse proportionality.
Inverse proportionality means that as one variable increases, the other variable decreases, while their product remains constant.
In this case, the current is inversely proportional to the resistance. So, we can set up an equation using the given values:
Current1 * Resistance1 = Current2 * Resistance2
Let's substitute the given values into the equation:
80 amps * 30 ohms = Current2 * 12 ohms
Now let's solve for Current2:
80 amps * 30 ohms / 12 ohms = Current2
Simplifying the equation:
(80 * 30) / 12 = Current2
2400 / 12 = Current2
200 = Current2
Therefore, when the resistance is 12 ohms, the current will be 200 amps.
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