×=50 + 30t -5t
a. Find the maximum height the particle attains
assuming you meant
h(t) = 50+30t-5t^2
= 5(10+6t-t^2)
max height is at t = -b/2a = 6/2 = 3
so, what is h(3)?
a. Find the maximum height the particle attains
h(t) = 50+30t-5t^2
= 5(10+6t-t^2)
max height is at t = -b/2a = 6/2 = 3
so, what is h(3)?