the sum of a 2 digit number is 6 when you reverse its digits you increase the number by 36 my answer is 3 is that correct
SteveI would like to see this problem worked out
How can 3 be a 2-digit number???
t = tens digit
u = units digit
so, the value of the number is 10t+u
t+u = 6
10u+t = 10t+u + 36
The number is 15
To verify if your answer is correct, let's break down the problem and solve it step by step.
Let's assume the two-digit number is represented by the tens digit 'x' and the units digit 'y'. The given conditions are:
1. The sum of the digits (x + y) is 6.
2. Reversing the digits results in a number 36 greater than the original number.
First, we can express the original number as 10x + y, since the tens digit represents a value in the tens place and the units digit represents a value in the ones place.
When we reverse the digits, the new number is represented by 10y + x.
According to the second condition, when we reverse the digits, the new number is 36 greater than the original number. Mathematically, we can write this as:
10y + x = (10x + y) + 36
Now, let's solve these equations simultaneously by substituting the first equation into the second:
10y + x = 10x + y + 36
Simplifying and rearranging the equation:
10y - y = 10x - x + 36
9y = 9x + 36
y = x + 4
Now, substitute this value of y into the first equation:
x + y = 6
x + (x + 4) = 6
2x + 4 = 6
2x = 2
x = 1
So, the tens digit (x) is 1.
Now, substitute this value of x into the equation y = x + 4:
y = 1 + 4
y = 5
Thus, the original number is 15.
To answer your question, No, your answer of 3 is incorrect. The correct answer is 15.