The school is selling tickets the first day the school sold 11 senior tickets and 4 child tickets a total of $93. the school sold $71 worth of tickets the second day 9 senior tickets and 2 child tickets find the price of a senior ticket and the price of a child ticket.
11s+4c = 93
9s+2c = 71
6.50 s 5.00 k
Steve I still don't no the answer to this question please help!
11s+4c = 93
9s+2c = 71
double the 2nd equation:
11s+4c = 93
18s+4c = 142
subtract the top from the bottom:
7s = 49
s = 7
11s+4c=93, so
77+4c = 93
4c = 16
c = 4
So, they sold 7 senior and 4 child tickets
To find the price of a senior ticket and the price of a child ticket, we can set up a system of equations using the given information.
Let's denote the price of a senior ticket as "S" and the price of a child ticket as "C."
From the first day's information, we know that 11 senior tickets and 4 child tickets were sold, resulting in a total of $93. So, we can create the first equation:
11S + 4C = 93
Similarly, from the second day's information, we know that 9 senior tickets and 2 child tickets were sold, resulting in a total of $71. This gives us the second equation:
9S + 2C = 71
Now we have a system of equations:
11S + 4C = 93
9S + 2C = 71
We can solve this system of equations using any method we prefer, such as substitution or elimination. Here, I will use the elimination method to solve it:
Multiply the second equation by 2 to make the coefficients of "C" the same, so we can eliminate "C" by subtracting the equations:
22S + 4C = 142 [2 * (9S + 2C) = 2 * 71]
11S + 4C = 93
Now, subtract the second equation from the first equation:
(22S + 4C) - (11S + 4C) = 142 - 93
Simplifying the equation:
11S = 49
Divide both sides of the equation by 11:
S = 49/11
Therefore, the price of a senior ticket is $4.45 (rounded to two decimal places).
Now, substitute the value of S into one of the original equations to find the price of a child ticket. Let's use the first equation:
11S + 4C = 93
11 * 4.45 + 4C = 93
49 + 4C = 93
Subtract 49 from both sides:
4C = 93 - 49
4C = 44
Divide both sides by 4:
C = 44/4
Therefore, the price of a child ticket is $11.
Hence, the price of a senior ticket is $4.45 and the price of a child ticket is $11.