Jason won some goldfish at the state fair.during first week,1/5 of them died, and during second week, 3/8 of those still alive are the end of the first week died.what fraction of the original goldfish were still alive after two weeks?
1 - 1/5 - (4/5)(3/8) = 1/2
Plug in a number for the amount of fish Jason won; let's say 20. One/fifth died after the first week, so that would be 4, leaving 16. After the second week, 3/8 of those died. Three/eighths of 16 would be 6. 16-6 is 10. 10/20ths would be 1/2, so C.
what do yiu it?
To find out what fraction of the original goldfish were still alive after two weeks, we need to calculate the fraction of goldfish that survived both the first and second weeks.
Let's start with the information given:
- During the first week, 1/5 of the goldfish died.
- This means that 4/5 of the original goldfish were still alive at the end of the first week.
- During the second week, 3/8 of those that were still alive at the end of the first week died.
To calculate the fraction of goldfish that survived after the second week, we need to multiply the fraction of goldfish that survived the first week by the fraction that survived the second week.
Fraction that survived the first week = 4/5
Fraction that survived the second week = 1 - 3/8 = 5/8
(Note: We subtract 3/8 from 1 because that is the fraction that died during the second week)
Now, to find the fraction that survived both weeks, we multiply the two fractions:
(4/5) * (5/8) = 20/40 = 1/2
Therefore, after two weeks, only 1/2 (or half) of the original goldfish were still alive.