A lift of height 3.375m is moving with acceleration of 2.2m/s2. What is the time required by any object to fall from the roof of the lift to the floor????

is the lift moving up or down

it makes a difference

To find the time required for an object to fall from the roof of the lift to the floor, we can use the equation of motion:

s = ut + (1/2)at^2

where:
s = height = 3.375m
u = initial velocity = 0 (since the object starts at rest)
a = acceleration = 2.2m/s^2
t = time

Since the object falls downward due to gravity, we consider the acceleration due to gravity as -9.8m/s^2 (taking it as negative because it is acting in the opposite direction of our positive direction).

Now, let's plug in the values into the equation and solve for t:

3.375 = 0 + (1/2)(-9.8)t^2
3.375 = -4.9t^2
t^2 = 3.375 / -4.9
t^2 = -0.68877

Taking the square root of both sides, we get:
t = √(-0.68877)

The square root of a negative number does not have a real solution in this context. This means that the object will not fall from the roof to the floor in this situation, as it defies the laws of physics.

Therefore, the time required for an object to fall from the roof of the lift to the floor in this scenario is not possible.