How to prepare 50ml 0.04N H2SO4 from solution 0.025N sulfuric acid by adding 0.4N sulfuric acid

let x = mL of 0.4

and 50-x = mL of 0.025
---------------------
0.025(50-x) + 0.4x = 50(.04)
solve for x and 50-x

To prepare a 50mL 0.04N H2SO4 solution from a 0.025N sulfuric acid solution by adding 0.4N sulfuric acid, you would follow these steps:

1. Determine the volume of the 0.025N sulfuric acid solution needed to achieve the desired concentration. Use the formula:
C1V1 = C2V2
Where C1 is the initial concentration (0.025N), V1 is the initial volume, C2 is the final concentration (0.04N), and V2 is the final volume (50mL).

Rearrange the formula to solve for V1:
V1 = (C2V2) / C1
V1 = (0.04N * 50mL) / 0.025N
V1 = 80mL

Therefore, you would need 80mL of the 0.025N sulfuric acid solution.

2. Now, determine the volume of the 0.4N sulfuric acid needed to make the final solution. Use the same formula:
C1V1 = C2V2
Where C1 is the initial concentration (0.4N), V1 is the initial volume, C2 is the final concentration (0.04N), and V2 is the final volume (50mL).

Rearrange the formula to solve for V1:
V1 = (C2V2) / C1
V1 = (0.04N * 50mL) / 0.4N
V1 = 5mL

Therefore, you would need to add 5mL of the 0.4N sulfuric acid solution.

3. Measure 80mL of the 0.025N sulfuric acid solution and transfer it to a container.

4. Measure 5mL of the 0.4N sulfuric acid solution and add it to the container with the 0.025N sulfuric acid solution.

5. Carefully mix the two solutions by gently swirling or stirring until they are thoroughly combined.

6. Finally, you would have a 50mL 0.04N H2SO4 solution prepared by adding the required volumes of the 0.025N and 0.4N sulfuric acid solutions.