*Please check to see if overall values are put in the right place!*
Type of metal used= Copper
Mass of metal object= 72.5 g
Specific heat of copper= .385 J/g C°
Mass of empty styrofoam cup= 3.264 g
Mass of styrofoam cup & water= 142.3 g
Temp of water (before)= 23.1 C°
Temp of water (after)= 59.1C°
Questions: (See if the proper values are put in each depending on what it's asking)
1. change in temp of water (Tf-Ti) = 59.1C° - 23.1 C° = 36.0C°
2. Initial mass of water heated (mass of styrofoam cup & water minus mass of empty sytrofoam) = 142.3g - 3.264 = 139.0g
3. heat gained by the water= mass * change in temp * sp. ht= 72.5 g * 36.0 C° * .385 J/gC° = 1004.85
* for this one, the mass that it's asking for is the mass of copper right? I assume but i'm not sure? also, if this were the mass I'd use, in Proper Sig Figs, would the answer be 100.4?
4. calculate temp of hot metal object: heat lost by metal= heat gained by water
* I was confused on this one.
Calculations Table: (for this, I confused with what values would be used where or what would be subtracted from what. Any clarification would be helpful)
A. Change of temp of water = 36.0 C°
B. Mass of water (initial)= 139.0 g
C. Heat absorbed by water= ?
D. Temp of hot, metal object = ?
E. Temp of Bunsen burner flame = ?
For the most part, I have the correct values!
I'm not sure EXACTLY what you did.
1 is OK
2 is OK
3 is not right. The mass H2O is 139.0 g and q = mc(dT). You didn't use specific hrat H2O as far as I can see.
4. Apparently you are to calculate the initial T of the metal.
[mass Cu x specific heat Cu x (Tf-Ti)] + [mass H2O x specific heat H2O x (Tf=Ti)] = 0.
Tf for Cu is same as Tf for H2O.
A is OK
B is OK
C is the asnwer from 3.
D is calculated with the formula I gave you in r.
E. Can't answer. I don't know enough about what you did and I don't see enough information to calculate the flam T.
To check if the overall values are in the right place, let's go through each question and calculation step by step:
1. Change in temp of water (Tf-Ti) = 59.1C° - 23.1C° = 36.0C°
The value you provided for the change in temperature of the water appears to be correct.
2. Initial mass of water heated (mass of styrofoam cup & water minus mass of empty styrofoam) = 142.3g - 3.264g = 139.0g
Again, the value you provided for the initial mass of water heated seems to be correct.
3. Heat gained by the water = mass * change in temp * sp. ht = 72.5g * 36.0C° * .385 J/gC° = 1004.85
In this calculation, the mass used should be the mass of water, not the mass of copper. So you should have: 139.0g * 36.0C° * .385 J/gC° = 1905.78 J. When rounding to proper significant figures, the answer should be 1906 J, not 100.4 J.
4. Calculate the temperature of the hot metal object: heat lost by metal = heat gained by water
To calculate the temperature of the hot metal object, you need to set up an equation using the heat lost by the metal and the heat gained by the water. However, you haven't provided the heat lost by the metal or any other values related to it in the given information. Without that information, it is not possible to calculate the temperature of the hot metal object.
Calculations Table:
A. Change in temp of water = 36.0C° (This is correct according to your earlier calculation)
B. Mass of water (initial) = 139.0 g (This is correct according to your earlier calculation)
C. Heat absorbed by water = ? (This value should be 1906 J, as explained earlier)
D. Temp of hot, metal object = ? (Without additional information, it cannot be calculated)
E. Temp of Bunsen burner flame = ? (This is not provided in the given information)
In summary, you have correctly calculated the change in temperature of the water and the initial mass of the water heated. However, the heat gained by the water should be 1906 J, not 100.4 J. The temperature of the hot metal object cannot be calculated without additional information, and the temperature of the Bunsen burner flame is not provided.