A body that uniformly retarded comes to rest in 5.0s after travelling a distance of 10.0m. Calculate the retardation and initial velocity
ave vel = 10.0 m / 5.0 s = 2.0 m/s
final is zero, so initial is ... 4.0 m/s
deceleration is
... 4.0 m/s / 5.0 s = 0.80 m / s^2
How was the initial velocity 4.0
To calculate the retardation, we can use the formula:
a = (v - u) / t
where:
a = retardation
v = final velocity (which is 0, as the body comes to rest)
u = initial velocity
t = time
Since the body comes to rest, the final velocity (v) is 0. So the formula becomes:
a = (0 - u) / t
Rearranging the formula to solve for retardation (a):
a = -u / t
Given: t = 5.0 s
Substituting the values we have:
0 = -u / 5.0
To solve for u (initial velocity), we need to rearrange the equation:
u = -0 * 5.0
Therefore, the retardation (a) is 0 m/s² and the initial velocity (u) is 0 m/s.