i did my question already but i was wondering if someone could double check my work.
the question says to graph the following function on the grpah
f(x)={|x|, -3 is equal to or less than x less than 2}
{2x-8, x less than or equal to 2}
i dont know if its possible to show a graph but mine has 2 functions. a v shaped one and liner one.they dont intercept and the liner one is below the v-shaped one
my x vales for 2x-8 were -2, -1, 0, 1, and 2. my y values were -12, -10, -8, -6, and -4
for |x| my x values are -2, -1, 0, 1, and 2. my y values are 2, 1, 0, 1, and 2.
the next part says to evaluate
F(0), i got |0| which equals 0
f(10), i did 2(10)-8 which equals 12
hope you can check it with this info
Everything you've mentioned is correct.
You might check that the boundaries are shown correctly:
The absolute value graph should have a solid circle at (-3, 3) and an open circle at (2, 2).
The linear function should have an arrow on the downward-left end and a solid circle at (2, -4).
Based on the information you provided, it seems like you have correctly graphed the two functions and evaluated the values of F(0) and f(10).
For the first part, to graph the function f(x) = {|x|, -3 ≤ x < 2} and {2x-8, x ≤ 2}, it appears that you have plotted a V-shaped graph representing the absolute value function f(x) = |x| for x values between -3 and 2. Then, you have plotted a linear function f(x) = 2x - 8 for x values less than or equal to 2. Since the linear function is below the V-shaped graph, it seems like you have accurately represented the two functions on the graph.
For the second part, you correctly evaluated F(0) and f(10).
- F(0) is equal to |0| which equals 0.
- f(10) is equal to 2(10) - 8 which equals 12.
Overall, based on the information you provided, it seems like you have correctly graphed the functions and evaluated the given values. However, if you have any additional concerns or if you would like further confirmation, please provide more details or ask specific questions.