A real estate salesperson bought promotional calendars and date books to give to her customers at the end of the year. The calendars cost
$0.750.75
each, and the date books cost
$0.500.50
each. She ordered a total of
500500
promotional items and spent
$275275.
How many of each item did she order
To find the number of each item she ordered, let's assume she bought "x" calendars and "y" date books.
According to the given information, each calendar costs $0.75 and each date book costs $0.50.
The total cost of calendars would be 0.75x, and the total cost of date books would be 0.50y.
We know that the total cost of all the promotional items is $275, so we can write the equation:
0.75x + 0.50y = 275.
We also know that the total number of promotional items is 500, so we can write the second equation:
x + y = 500.
We now have a system of two equations:
0.75x + 0.50y = 275
x + y = 500.
To solve this system of equations, we can use substitution or elimination method. I'll use the elimination method:
Multiply the second equation by 0.50:
0.50x + 0.50y = 250.
Now subtract this equation from the first equation:
0.75x - 0.50x + 0.50y - 0.50y = 275 - 250
0.25x = 25
x = 25 / 0.25
x = 100.
Substituting this value back into the second equation:
100 + y = 500
y = 500 - 100
y = 400.
Therefore, the real estate salesperson ordered 100 calendars and 400 date books.
c+d = 500
.75c + .50d = 275