A 5 kg block rests on a frictionless horizontal surface. A cord attached to the block passes over the pulley whose diameter is 0.120 m to the hanging block of mass 5 kg. The system is released from rest and the blocks are observed to move 3m in 2.0 s.

A. What is the tension in each part of the block?
B. What is the moment of inertia of the pulley?

To solve this problem, we need to use the principles of Newton's laws of motion and rotational motion. Let's break it down step by step:

A. To find the tension in each part of the block, we need to analyze the forces acting on the system.

1. For the hanging block (mass 5 kg):
The only force acting on it is its weight, which can be calculated as:
Weight = mass * acceleration due to gravity
Weight = 5 kg * 9.8 m/s^2
Weight = 49 N (Newtons)

2. For the block on the horizontal surface (also 5 kg):
Since the surface is frictionless, there are no horizontal forces acting on it.

3. For the pulley:
The tension in the cord is the same on both sides of the pulley.

Now, let's analyze the motion of the system:
The system is released from rest and observed to move 3 m in 2.0 s. Using the equation of motion:
Displacement = (initial velocity * time) + (0.5 * acceleration * time^2), we can find the acceleration of the system.

Displacement = 3 m
Initial velocity = 0 (as the system is released from rest)
Time = 2.0 s

Using the above equation, we rearrange it to solve for acceleration:

Acceleration = (Displacement - (initial velocity * time)) / (0.5 * time^2)
Acceleration = (3 m - (0 * 2.0 s)) / (0.5 * (2.0 s)^2)
Acceleration = (3 m) / (0.5 * 4.0 s^2)
Acceleration = 1.5 m/s^2

Now, let's analyze the forces acting on the system using Newton's second law:
1. For the hanging block:
The net force acting on the hanging block is equal to its mass multiplied by its acceleration.
Net force = mass * acceleration
49 N - Tension = 5 kg * 1.5 m/s^2
49 N - Tension = 7.5 N
Tension = 49 N - 7.5 N
Tension = 41.5 N

2. For the block on the horizontal surface:
Since there are no horizontal forces acting on this block, the tension in the cord provides the force required to accelerate it.
Tension = mass * acceleration
Tension = 5 kg * 1.5 m/s^2
Tension = 7.5 N

Therefore, the tension in each part of the block is 41.5 N and 7.5 N.

B. To calculate the moment of inertia of the pulley, we need to know the mass or density of the pulley and its geometry.

If we assume that the pulley is a uniform disk, we can use the formula for the moment of inertia of a disk.

Moment of inertia for a uniform disk = (1/2) * mass * radius^2

However, we need either the mass or the density of the pulley to calculate its moment of inertia. If you have that information, you can substitute it into the formula to find the moment of inertia.