A cord can b streated to it elastic limit by 2N.if a 35m of d cord by 0.6 By a force of 0.5n wat wil b d L wendforce2.5n
To determine the change in length (ΔL) when a force is applied to a cord, we can use Hooke's Law, which states that the force applied to a spring or elastic material is directly proportional to the extension or compression of the material.
Hooke's Law can be expressed as:
F = k * ΔL
where F is the force applied, k is the stiffness constant (also known as the spring constant), and ΔL is the change in length.
Given that the cord can be stretched to its elastic limit by 2N and a 35m length of the cord is stretched by 0.6m with a force of 0.5N, we need to find the value of k.
First, we can calculate the stiffness constant (k) using the given information:
k = F / ΔL
k = 0.5N / 0.6m
k ≈ 0.833 N/m
Now that we have the value of k, we can calculate the change in length (ΔL) when a force of 2.5N is applied:
ΔL = F / k
ΔL = 2.5N / 0.833 N/m
ΔL ≈ 3m
Therefore, the change in length (ΔL) when a force of 2.5N is applied to the cord would be approximately 3 meters.