y + ((4x^2)/(3-x)) ^3

y ' = ?

Product Rule didn't work here ...I think the Quotient rule but the cube on end has me stumped

If you let

u = 4x^2
v = 3-x
then you have
y = (u/v)^3
y' = 3(u/v)^2 (u/v)'
= 3(u/v)^2 ((u'v-uv')/v^2)
= 192x^5(6-x) / (3-x)^4