1)A pocket of gas is discovered in a deep drilling operation. The gas has a temperature of 480c and is at a pressure of 12.8 atm. What volume of gas is required to provide 18.0 L of gas at the surface where the conditions are 22 C and 1.00 atm?

is this correct for number 1?
480c = 753k, 22c = 295k
p1 x v1/T1 = p2 x v2/T2
12.8 x v1/753 = 1.00 x 18.0/295
.016 = .061

.016 is V1

Hmmm. Put this in your calc or the google search window:
18* 1/12 * 753/295

I get almost 4 liters.

What is the volumeof 45.0 grams of NO at 20 c and a pressure of 740 mm Hg?

2) The molar mass is 16 + 12 = 28.00, so
45.0 g is n = 1.61 moles. That number of moles would occupy
22.4 x 1.61 = 36.06 liters at 1.00 atm and 273 K. At 20 C and 740 mm Hg. Now what?

First, recalcualte the molar mass of NO. I get more like 30 than 28.
Then solve one of two ways.
Use your NEW volume (using the correct molar mass) and P1V1/T2 = P2V2/T2 OR
use PV = nRT where n is the NEW number of mols.
The answer is about 37 L or so.

To solve the first problem:

1) Begin by converting the temperatures from Celsius to Kelvin. To convert from Celsius to Kelvin, you add 273 to the Celsius value. So, 480°C becomes 753K and 22°C becomes 295K.

2) Using the ideal gas law equation, which states that p1 x v1 / T1 = p2 x v2 / T2, you can solve for v1, which is the volume of gas at the initial conditions.

Substituting the given values, you have: 12.8 x v1 / 753 = 1.00 x 18.0 / 295

3) Now, to find v1, isolate it by multiplying both sides of the equation by 753 and dividing by 12.8:

v1 = (1.00 x 18.0 x 753) / (12.8 x 295)
v1 ≈ 4 liters

So, the correct answer should be around 4 liters.

To solve the second problem:

1) Calculate the molar mass of NO by adding the atomic masses of nitrogen (N) and oxygen (O). Nitrogen has a molar mass of 14 g/mol, and oxygen has a molar mass of 16 g/mol. So, the molar mass of NO is 14 + 16 = 30 g/mol.

2) Now, calculate the number of moles (n) of NO by dividing the given mass (45.0 g) by the molar mass:

n = 45.0 g / 30 g/mol
n ≈ 1.5 moles

3) Using the ideal gas law equation or the volume formula PV = nRT, you can calculate the volume at the given conditions.

Using the formula p1 x v1 / T1 = p2 x v2 / T2, with p1 = 740 mmHg, T1 = 293 K (20°C + 273), p2 = 1 atm (convert mmHg to atm), and T2 = 273 K (standard temperature), we can solve for v2.

p2 = 740 mmHg / 760 mmHg/atm ≈ 0.974 atm

v2 = (p1 x v1 x T2) / (p2 x T1)
v2 = (0.974 x 36.06) / (1 x 293)
v2 ≈ 37 liters

So, the correct answer should be around 37 liters.