Calculate the percentage of acetic acid used in 2.1g of acetic acid that was titrated against 0.1M NaOH
To calculate the percentage of acetic acid in 2.1g of acetic acid, we need to know the molecular weight of acetic acid (CH₃COOH).
The molecular weight of acetic acid is calculated by adding up the atomic weights of its constituent elements: C (carbon), H (hydrogen), and O (oxygen).
C: 1 atom * 12.01 g/mol = 12.01 g/mol
H: 4 atoms * 1.01 g/mol = 4.04 g/mol
O: 2 atoms * 16.00 g/mol = 32.00 g/mol
Adding these together gives us a molecular weight of:
12.01 g/mol + 4.04 g/mol + 32.00 g/mol = 48.05 g/mol
Now we can use this molecular weight to calculate the percentage of acetic acid in 2.1g of acetic acid.
Percentage of acetic acid = (mass of acetic acid / total mass) * 100
Mass of acetic acid = 2.1g
Total mass = 48.05 g/mol
Percentage of acetic acid = (2.1g / 48.05 g/mol) * 100 = 4.37%
Therefore, the percentage of acetic acid in 2.1g of acetic acid is approximately 4.37%.