How would you write the chemical equation for sodium nitrate + isopropyl alcohol.
So it would be NANO3 (aq) + C3H8O (aq) ->
But I'm not sure how to find the products, thanks for your help!
I'm blank on this.
To write the chemical equation for the reaction between sodium nitrate (NaNO3) and isopropyl alcohol (C3H8O), you need to consider the reaction between the sodium ion (Na+) and the nitrate ion (NO3-) on one side, and the isopropyl alcohol (C3H8O) on the other side.
When sodium nitrate, which is an ionic compound, is dissolved in water (denoted by (aq)), it dissociates into its constituent ions:
NaNO3 (aq) → Na+ (aq) + NO3- (aq)
Isopropyl alcohol, on the other hand, remains as a molecular compound in aqueous solution.
Now, to find out if a reaction occurs between these two compounds, you need to determine if a chemical change is possible. Generally, chemical reactions occur when there is a possibility of forming new bonds or breaking existing bonds.
In this case, sodium nitrate does not react with isopropyl alcohol under normal conditions. Therefore, no new products are formed in this reaction.
Thus, the balanced chemical equation for the reaction between sodium nitrate and isopropyl alcohol would simply be:
NaNO3 (aq) + C3H8O (aq) → No reaction
It is important to note that not all combinations of substances will undergo a chemical reaction. In cases like this, where no reaction occurs, the chemical equation will reflect that by showing "No reaction" or an arrow crossed out.