A seagull drops a claim from a height of 40m above the rocks. If the air temperature is 0 degrees C, how long after the claim is dropped does the sound of it drinking the rocks directly below reach the seagull? Assume that the seagull hovered in place during the drop..

Question

A seagull drops a claim from a height of 40m above the rocks. If the air temperature is 0 degrees C, how long after the claim is dropped does the sound of it drinking the rocks directly below reach the seagull? Assume that the seagull hovered in place during the drop..

So what I did is:

V=331+0.61*0
V=331m/s

x=v/t
40m=331m/s/f
F = 8.3Hz

Fobs = (331m/s + 0m/s / 331m/s + vsource) / 8.3
Fobs = 8.3hz

So therefore x = v/t
331 = 8.3 /t
T = 0.25s

I'm not sure if this is right though, and I don't know if the whole fobs thing was necessary. Thanks for the help!

Answer 1

A seagull drops a claim from a height of 40m above the rocks. If the air temperature is 0 degrees C, how long after the claim is dropped does the sound of it drinking the rocks directly below reach the seagull? Assume that the seagull hovered in place during the drop..

what about the time it takes for the clam to fall 40 m?