# algebra

A church group has a fund raiser in which they raise \$2,040.00. If there were 69 more people then everyones donations would be \$23.00 less. How many members were there originally and how much did they donate?

let n be the number of folks
let D be the donation per person

n*D=2040
(n+69)(d-23)=2040

With those two equations, it ought to work out. Repost if you have difficulties.

I've studied this several ways.

There are a few different equations that can be defined to represent the given conditins.

One is:

Let N = the initial number of contributors and d = the initial donations.

Then, Nd = 2040 and N(d - 23) + =69(d - 23) = 2040.

Substituting and simplifying yields d = 23 + N/3.

N must be divisible by 3.

N......3...6...9.......--->
Nd....72..150..234....---->

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