If a spinner is spun twice what is the probability that the arrow will stop ona vowel both times?
Letters are: T, A, D, U, P,I
A. 2/9
B. 1/4
C. 1/3***
D. 11/36
Is not an answer.
You're welcome.
I did and I got 0.25.I don't get it.....WAIT I think it would be 1/4. Is that right?
Yes, 1/4 is right.
Thank you so much Ms. Sue!!!! And Thank you too Scott!!!!
how is it 1/4
To find the probability that the arrow will stop on a vowel both times when the spinner is spun twice, we need to determine the total number of possible outcomes and the number of favorable outcomes.
First, let's find the total number of possible outcomes. Since the spinner is spun twice, there are six possible outcomes each time it is spun. Therefore, the total number of possible outcomes for two spins is 6 * 6 = 36.
Next, let's determine the number of favorable outcomes. The vowels in the given letters are A, U, and I. Since there are three vowels out of a total of six letters, the probability of getting a vowel on a single spin is 3/6 = 1/2. Since we need the arrow to stop on a vowel both times, we multiply the probabilities together: (1/2) * (1/2) = 1/4.
Therefore, the probability that the arrow will stop on a vowel both times is 1/4.
So, the correct answer is B. 1/4.
Multiply, as Scott told you.
(1/2) * (1/2) = ?
half of the letters are vowels
so, one half times one half