calculate the molarity of sodium carbonate in a solution prepared by dissolving 5.3g in enough water to form 250ml of solution
M = molarity = mols/L
How many mols? That's mols = grams/molar mass
L = 0.250
To calculate the molarity of sodium carbonate in a solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to find the moles of sodium carbonate. We can use the formula:
moles = mass / molar mass
The molar mass of sodium carbonate (Na2CO3) is:
2(22.99 g/mol) + 1(12.01 g/mol) + 3(16.00 g/mol) = 105.99 g/mol
Now we can calculate the moles of sodium carbonate:
moles = 5.3 g / 105.99 g/mol = 0.05 moles
Next, we need to convert the volume of the solution from milliliters (ml) to liters (L).
250 ml = 250 / 1000 = 0.250 L
Now we plug the values into the formula for molarity:
Molarity (M) = 0.05 moles / 0.250 L = 0.20 M
Therefore, the molarity of sodium carbonate in the solution is 0.20 M.