Find the horizontal distance a ball travels after 3 seconds, if the ball is hit with an initial velocity of 90 feet per second at an angle of 60 degrees from an initial height of 5 feet.
Round answer to nearest tenth, if necessary. Do not include units.
see your previous post. The horizontal speed is constant.
To find the horizontal distance a ball travels, we need to consider the horizontal component of its initial velocity.
The horizontal component of the initial velocity can be calculated using the equation:
Vx = V * cos(theta)
where Vx is the horizontal component of the velocity, V is the magnitude of the initial velocity, and theta is the angle of the initial velocity.
In this case, the initial velocity (V) is 90 feet per second and the angle (theta) is 60 degrees.
Vx = 90 * cos(60)
Next, we need to calculate the time it takes for the ball to travel horizontally. Since there is no horizontal acceleration, the time is the same as the total time of flight (t).
t = 3 seconds
Finally, we can calculate the horizontal distance (d) traveled by the ball using the equation:
d = Vx * t
Substituting the values we found earlier:
d = (90 * cos(60)) * 3
Evaluate the equation and round the answer to the nearest tenth if necessary to get the final result.