The difference of two number is 33. the larger number is one more tHan three time the smaller number .find the number.

let the smaller be x

then the larger is x+33

(x+33) - 3x = 1

easy to solve.

To find the two numbers, let's say the smaller number is x. According to the given information, the larger number is one more than three times the smaller number. So, the larger number can be represented as 3x + 1.

The difference between the two numbers is given as 33. This can be written as:

3x + 1 - x = 33

Now, let's solve this equation to find the value of x:

2x + 1 = 33 (combining like terms)

2x = 33 - 1 (subtracting 1 from both sides)

2x = 32 (simplifying)

x = 32/2 (dividing both sides by 2)

x = 16

So, the smaller number is 16.

To find the larger number, substitute the value of x back into the expression we got: 3x + 1.

Since x = 16:

3(16) + 1 = 48 + 1 = 49

Therefore, the larger number is 49.

In conclusion, the smaller number is 16 and the larger number is 49.