C (s) + S2 (g) = CS2 (g) . Kp=5.6
At equilibrium, P cs2 = 0.152 atm. Find P s2
How would I start this problem?
Set up Kp expression.
You know Kp and pCS2. Solve for pS2 at equilibrium. Remember not to include C(s) in the expression.
Kp = 5.6 - pCS2/pS2
To solve this problem, you need to use the expression for the equilibrium constant (Kp) and the given value of the equilibrium partial pressure of CS2 (Pcs2) to find the value of Ps2.
1. Start by writing the balanced chemical equation:
C (s) + S2 (g) ⇌ CS2 (g)
2. Use the equilibrium constant expression (Kp) to write the equilibrium expression:
Kp = (Pcs2) / (Pc * Ps2)
where Pcs2, Pc, and Ps2 are the partial pressures of CS2, C, and S2, respectively.
3. Substitute the known values into the equation:
Kp = 5.6
Pcs2 = 0.152 atm
4. Rearrange the equation to isolate Ps2:
Ps2 = (Pcs2) / (Pc * Kp)
Since the partial pressure of a solid (C) is constant and does not appear in the equilibrium expression, it can be ignored. So, Pc = 1.
5. Plug in the given values:
Ps2 = (0.152 atm) / (1 * 5.6)
6. Solve for Ps2:
Ps2 = 0.027 atm
Therefore, the partial pressure of S2 (Ps2) at equilibrium is 0.027 atm.