Juggle and bangles are clowns.juggles stands on one end of a teeter-Ritter at rest on the ground.bangles jumps off a platform 2.5m above the ground and lands on the other end of the teeter-totter,launching juggles into the air.juggles rises to a height of 3.3m above the ground, at which point he has the same amount of gravitational potential energy as bangles had before he jumped, assuming both potential energies are measured using the ground as the reference level.bangles mass is 86 kg.what is juggle 's mass?
the masses are inversely proportional to the heights
... higher height means lower mass
Hb Mb = Hj Mj
To solve this problem, we need to recognize that the gravitational potential energy of an object is given by the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth), and h is the height relative to the reference level.
Since both Juggles and Bangles have the same amount of gravitational potential energy, we can equate their respective potential energies.
Let's calculate Bangles' potential energy first:
PE_bangles = m_bangles * g * h_bangles
PE_bangles = 86 kg * 9.8 m/s^2 * 2.5 m
PE_bangles = 2113 J
Now we can equate the potential energy of Juggles to Bangles' potential energy:
PE_juggles = PE_bangles
m_juggles * g * h_juggles = PE_bangles
m_juggles * 9.8 m/s^2 * 3.3 m = 2113 J
Solving for m_juggles:
m_juggles = 2113 J / (9.8 m/s^2 * 3.3 m)
m_juggles ≈ 65 kg
Therefore, Juggles' mass is approximately 65 kg.