Two point charges of equal magnitude are seperated by a distance of 12cm in air.An attractive force of 90N acts on each charge.What are the charges
force=kqq/.12^2
q=.12 sqrt(force/k)
if force is 90N, with k, this works out nicely.
12 x 10^(-6)
To determine the charges of the two point charges, we can use Coulomb's law, which states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula for Coulomb's law is:
F = k * (q1 * q2) / r^2
Where:
- F is the magnitude of the electrostatic force
- k is the electrostatic constant (9 x 10^9 Nm^2/C^2)
- q1 and q2 are the charges of the two point charges
- r is the distance between the charges
In this case, we know that the attractive force acting on each charge is 90N, and the distance between them is 12cm (which we'll convert to meters). We can set up the equation as follows:
90N = (9 x 10^9 Nm^2/C^2) * (q1 * q2) / (0.12m)^2
Simplifying the equation, we get:
(q1 * q2) = (90N * (0.12m)^2) / (9 x 10^9 Nm^2/C^2)
(q1 * q2) = 0.0012 C^2
Now, let's factorize the product of the charges:
(q1 * q2) = (q1)^2 = (q2)^2
0.0012 C^2 = (q1)^2
Taking the square root of both sides, we find:
q1 = sqrt(0.0012 C^2)
q1 ≈ 0.0346 C
Since both charges have equal magnitude, q2 will also be approximately 0.0346 C.
Therefore, the charges of the two point charges are approximately 0.0346 C.