int (30y1y2)dy1 ?
If y2 is constant, you have
30 y2 integral y1 dy1
which is
30 y2 (1/2) y1^2 + arbitrary constant
yeah that's what i thought it was, i guess i am not settin my limits up properly ...but yeah y2 is constant. thanks
To evaluate the integral ∫(30y^1y^2)dy^1, we need to follow these steps:
Step 1: Distribute the multiplication
We have 30y^1 * y^2. Multiplying the exponents, we get y^(1+2) = y^3. So, the expression becomes 30y^3.
Step 2: Integrate the expression
To integrate 30y^3 with respect to y, we follow the power rule of integration. The power rule states that for any term of the form y^n (where n is any real number except -1), the integral is (1/n+1) * y^(n+1).
In our case, n = 3. So, we apply the power rule:
∫30y^3 dy = (30/4) * y^(3+1) + C
= (30/4) * y^4 + C
So, the final result of the integral is (30/4) * y^4 + C, where C is the constant of integration.