# Chemistry

Calculate the freezing point depression and osmotic pressure at 25 degrees C of an aqueous solution of 1.0 g/L of a protein (mol wt= 90,000) if the density of the solution is 1.0 g/mL.

I know how to calculate freezing point depression and osmotic pressure, but I'm having trouble calculating the molarity and molality to use in the equations. Any help would be appreciated. Also, with the way the information is given, does the 90,000 count for sig figs or is it a "known value"?

With the way 90,000 is listed (no period at the end), we REALLY don't know. Technically it has only one s.f.. It is a measured value.
molality = mols/kg solvent
mols=g/molar mass. I assume the concentration of the protein is 1.0g/L if I read the problem correctly.
Thus, the #mols = 1.0/90,000 = ??
So molarity = # mols/L = ??M

For such small concentrations AND with the density of the solution being 1.0 g/L, won't the molality and molarity be the same? Check my thinking.

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