Ronald lee has been told by a company that the probability he will be offered a job in the quality control department is .6 and the probability he will be asked to be foreman of the department, if he offered the job is .1. what is the probability that he will be offered the job and asked to be foreman?
So basically he has a (6/10) chance of being offered a job and (1/10) of becoming foreman. Multiply those together get you (6/100) reduced that (3/50). Basically a 6% chance to get the job and become foreman.
To find the probability that Ronald Lee will be offered the job and asked to be the foreman, we can use the concept of conditional probability.
Let's assign the following probabilities:
P(Offered the job) = P(O) = 0.6
P(Asked to be foreman | Offered the job) = P(F | O) = 0.1
We want to find the probability of both events occurring, which can be calculated using the formula for conditional probability:
P(O and F) = P(O) * P(F | O)
Substituting the given probabilities:
P(O and F) = 0.6 * 0.1 = 0.06
Therefore, the probability that Ronald Lee will be offered the job and asked to be the foreman is 0.06 or 6%.