. Ethyl alcohol has been added to 160 mL of water in a container that has a mass of 130 g when empty. The resulting container and liquid mixture has a mass of 510 g .What volume of alcohol was added to the water? (in mL)
Total mass = water mass + alcohol mass + continer mass.
The mass of alcohol added was 510 - 130 - 160 g = 220 g, since the 160 mL of water had a mass of 160 g.
Thanks a lot
To find the volume of alcohol added to the water, we need to determine the mass of the alcohol first.
1. Determine the mass of water: 510 g - 130 g = 380 g
2. Convert the mass of water to volume using the density of water: 1 g/mL
Volume of water = Mass of water / Density of water = 380 g / 1 g/mL = 380 mL
3. Subtract the volume of water from the total volume to find the volume of alcohol.
Volume of alcohol = Total volume - Volume of water = 160 mL - 380 mL = -220 mL
From the calculation, we end up with a negative value for the volume of alcohol, which doesn't make physical sense. It suggests an error in the information or calculation process. Please recheck the values or the problem statement.