Science - physics

the fence posts around a large pasture are 2.5m apart. a horse starts running west beside the fence. when the horse passes the fifth fence post, your second hand is on the 9.0 mark. when the horse passes the fourteenth fence post, the second hand is on 11.5 seconds. what is the horse’s velocity?

Not sure how to do this at all. Can I please get help and can I get an explanation at each step and work as well? Thank you!

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  1. The time was measured at post 5 and post 14.
    The number of post gaps between post 5 and post 9 is 14 - 5 = 9
    We know each post gap is 2.5 m long.
    So the horse ran 2.5 m x 9 = 22.5 m West
    This displacement of the horse occurred in 11.5 s - 9 s = 2.5 s.
    Velocity = displacement / time
    = 22.5 m / 2.5 s = ____ m/s West

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  2. 9.0 m/s west

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