Use the atomic weight of carbon and chlorine to determine the theoretical value of the molecular weight of CH3OH Or methanol.( atomic weights (c=12, cl=35.5).
if you in the lab manual of CHFO2 I Advice you that the question is error we find the question is asking about hydrogen and the carbon atomic weight instead of chlorine and carbon dioxide therefore get it rightly and answer the question your answer should be 16 g/mol.
And what other information do you have available. You must have some way to calculate atomic masses of O and H. Or is it OK to look those up on the periodic chart.
To find the molar mass of hydrogen and carbon we use the formula of CH3OH
Therefore
H=1x3g/mol + 1 g/mol=4 g/mol
C=12g/mol therefore the total molar mass is 12g/mol + 4g/mol =16 g/mol
And then to get the molar mass of the CH3OH
We add the molar of hydrogen and carbon dioxide with the molar of oxygen and with it
Therefore the molar mass of oxygen is equal to 16 g/mol
Total molar mass of the methanol is equal to 16g/mol + 16g/mol=32 g/mol.
To get the error that is present we minus the real or origin value of methanol molar mass with the sample we prepared in the; lab.
To determine the theoretical value of the molecular weight of CH3OH (methanol), we need to know the atomic weights of all the elements present in its formula. In this case, we have carbon (C), hydrogen (H), and oxygen (O).
The formula of methanol is CH3OH.
The atomic weight of carbon (C) is given as 12, which means one carbon atom weighs 12 atomic mass units (amu).
The atomic weight of hydrogen (H) is approximately 1.01 amu, which can be rounded to 1.
The atomic weight of oxygen (O) is approximately 16 amu.
Now, to calculate the molecular weight of CH3OH, we need to sum up the atomic weights of each atom in the formula.
(1 x atomic weight of C) + (4 x atomic weight of H) + (1 x atomic weight of O)
= (1 x 12) + (4 x 1) + (1 x 16)
= 12 + 4 + 16
= 32
Therefore, the theoretical molecular weight of CH3OH or methanol is 32 amu.