Let f(x)=81+3e−0.7x .
What is the value of f(3) ?
Round the answer to the nearest hundredth.
Enter your answer in the box.
idk how to do this :/
just replace x with 3. Same as you have done for the last year or so in algebra...
f(3) = 81 + 3e^(-0.7*3)
= 81 + 3e^-.21
= 81 + .81058
= 81.81058
Better get out your calculator (physical or online) for these!
To find the value of f(3), substitute the value of x as 3 in the function f(x)=81+3e^(-0.7x).
Plug in x = 3:
f(3) = 81 + 3e^(-0.7 * 3)
Now multiply -0.7 by 3:
f(3) = 81 + 3e^(-2.1)
Next, use a calculator to evaluate e^(-2.1):
f(3) = 81 + 3 * (approximately 0.1221)
Multiply 3 by 0.1221:
f(3) = 81 + (approximately 0.3663)
Add 81 and the approximate value:
f(3) ≈ 81.3663
Rounded to the nearest hundredth, the value of f(3) is approximately 81.37.
To find the value of f(3), you need to substitute x = 3 into the given function, f(x) = 81 + 3e^(-0.7x).
Let's do the calculation step by step:
Step 1: Substitute x = 3 into the function:
f(3) = 81 + 3e^(-0.7*3)
Step 2: Multiply -0.7 by 3:
f(3) = 81 + 3e^(-2.1)
Step 3: Calculate e^(-2.1) using a calculator or the exponential function:
f(3) ≈ 81 + 3*(0.122) [rounding the value of e^(-2.1) to the nearest thousandth]
Step 4: Multiply 3 by 0.122:
f(3) ≈ 81 + 0.366
Step 5: Add 81 and 0.366:
f(3) ≈ 81.366
Therefore, the value of f(3) is approximately 81.366 when rounded to the nearest hundredth.