the ships leaves a port with a constant course and constant speed. after 2 hours the ship is 55miles south and 20 miles west of port. what is its course and speed?
Let x=east, y=north, then
the location of the ship after two hours is
(-20, -55)
Since it has constant course and speed, after one hour, it is at
(-10,-27.5)
The course is tan-1(-10/(-27.5)) west of south, and the speed is the distance travelled, using Pythatorean theorem,
s=sqrt(-10)²+(-27.5)²)
First try to understand the above calculations. If so, take out your calculator and find the answers. If not, please post any question you have.